An yi wannan darasi da wani Local Solar System ma'aikacin ƙungiyar Foundation kuma za'a iya inganta shi da mai duba da ya dace. Shin kana da kwarewa a cikin wannan batutuwa? Suggest an edit
A cikin 1903 wani malamin makarantar da ya yi rauni a Kaluga, Konstantin Tsiolkovsky, ya rubuta ƙaddarorin da ke ci gaba da girman kowane roketi. Yana bayyana dalilin da ya sa wani Falcon 9 ne game da 89% propellant, me ya sa dauke shi ne kawai kaɗan cikin dari na nauyin a liftoff, kuma me ya sa rokets rasa wasu sassa na kansu a kan hanyar zuwa sama.
Duk wani roketi ne gasar tsakanin da sauri kana so da kuma nauyin da ka kamata a yi don su samu shi.
Look
Wani roketi yana tafiya ne da jefar da wani abu zuwa bãya. Ka jẽfa, kõ ka ƙãra wani abu daga gare shi, idan kã so ka kasance mafi gaggãwar tafiya.” Akwai wani kama: mai da ba ka shafe har yanzu dole ne kuma a kai da kuma gaggauta. Wancan ne yake saukar da alhẽri. logarithmic: don ƙara irin wannan adadin gudun, dole ne ka ninka mai, ba ka ƙara shi ba.
Delta-v (Δv, “canje a cikin gudu”) shine kudin shiga na jirgin sama. Duk wani jujjuyawar yana da farashinsa cikin kilomita/s:
- Fuskar ƙasa zuwa orbit mai ƙananan: kusan 9.4 km / s, gami da asarar.
- low orbit to geostationary orbit: about 3.9 km/s.
- low orbit to leave Earth for Mars: about 3.6 km/s.
Kudin jirgin sama shi ne yadda yawa Δv na injiniyoyinsa, mai da kuma nauyin zai iya bayarwa.
Understand
Δv = I_sp · g₀ · ln(m₀ / m_f)
- I_sp: Ƙaramar ƙarfi, ma’aunin ingancin injin cikin sakan (gudun fitarwa an raba shi da g₀).
- g₀ = 9.80665 m/s², ma’auni na jujjuyawar duniyar.
- m₀: nauyin a farkon rubu’in; m_f: nauyin a ƙarshe.
Misali da mataki na biyu na roket ɗin simulation (Isp 348 s): cikakke, yana nauyin kusan tan 112 ciki har da nauyin 15-ton; ba tare da propeller ba, kusan tan 19. Δv = 348 × 9.81 × ln(112 / 19) ≈ 6.0 km/s. Mataki na farko yana ƙara sauran.
A matakin daya da wani nau’i na 10 da Isp 350 s ba kawai 7.9 km / s, ba da yawa ga orbit lokacin da asarar aka lissafa, kuma wani tsari wanda ne kawai 10% na duka ne yanzu haske sosai. Wannan shi ne dalilin da ya sa kusan kowace roket mai tafiyar hawa biyu ke amfani da matakai biyu ko fiye.
Master
Staging multiplies mass ratios. Domin wani biyu-mataki jirgin sama,
Δv_total = I₁ g₀ ln(m₁₁/m_f₁) + I₂ g₀ ln(m₀₂/m_f₂)
A inda ma’aunin farawa na mataki na biyu ya ƙunsa duk abin da mataki na farko ya jefa. Optimizing da rarraba tsakanin matakai (ga daidai Isp, kusan daidai Δv a kowace mataki) shi ne wani classic matsala: the payload fraction ya fadi exponentially tare da bukata Δv, wanda shi ne dalilin da ya sa rage da Δv zuwa orbit ta wasu ɗaruruwan m / s (launching gabas, kusa da equator) muhimmanci sosai.
The equation kuma bayyanar da manhajar na sake amfani da farko matakai: su tashi baya amfani da mai da za a in ba haka ba ya kasance da damar yi, ciniki kaɗan bisa dari na nauyin don ba a jefa daga cikin mafi tsada sashi na roket.
Try it
Da amfani da Δv = Isp · g₀ · ln(m₀/m_f), ka gano adadin nauyi da wata roket mai mataki guda da Isp = 350 s za ta bukata domin 9.4 km/s. Mene ne kashi na nauyin tashinta zai iya zama ginin da nauyin amfani?
Great. kalubale ne inda koyon sticks.
Quick quiz
3 tambayoyi masu sauri. Zaɓi amsa don ka ga ko kai mai gaskiya ne.
-
A cikin ma'ana na roket, yin ninka adadin nauyin (m₀/m_f) yana da tasiri akan delta-v?
- A Doubles it
- B Adds a fixed amount (Isp · g₀ · ln 2)
- C Halves it
- D Nothing
Nuna amsa
B. Adds a fixed amount (Isp · g₀ · ln 2) Delta-v na girma tare da logaritmin adadin nauyin: kowace ninkawa tana ƙara daidai, kusan 2.4 km/s ga Isp 350 s.
-
Me ya sa ake nufi da wani ƙarfin motsi na musamman mai girma (Isp)?
- A A larger rocket
- B Faster exhaust, so more delta-v from the same fuel
- C More thrust
- D A heavier engine
Nuna amsa
B. Faster exhaust, so more delta-v from the same fuel
-
Me ya sa wannan yake taimakawa?
- A An yi amfani da tankuna da injiniyoyi marasa nauyi, don haka a baya za'a iya kashe su cikin sauri
- B Yana sa jirgin sama ya fi aerodynamic
- C An ƙona matakai a lokaci guda
- D Kuma yana ƙãra wutar lantarki a cikin tafiyarsa.
Nuna amsa
A. An yi amfani da tankuna da injiniyoyi marasa nauyi, don haka a baya za'a iya kashe su cikin sauri
Finish line
- Read the lesson
- Did the challenge
- Took the quiz
Mark the lesson complete to save it to your progress on this device.
An kammala darasi. Mai kyau!
Up next Hohmann ya canja: canja orbitsWords in this lesson
Sources
- K. Tsiolkovsky, Exploration of Outer Space by Means of Reaction Devices (1903), NASA history summary
- NASA Glenn Research Center, Ideal rocket equation
- SpaceX, Falcon User's Guide (2021)
- H. D. Curtis, Orbital Mechanics for Engineering Students, 4th ed., ch. 13
Wannan darasi yana da lasisin CC BY-SA 4.0.