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لټول · رغبېلګه 12

Gravity assists: the free slingshot

How Voyager, Cassini and New Horizons stole speed from planets, and why it never breaks the conservation of energy.

12 منټ

NASA/JPL/Space Science Institute

دا درس د Local Solar System بنسټ ټیم غړی لخوا لیکل شوی و او کیدای شي د یو وړ کتنه کونکي لخوا ښه شي. تاسو په دې موضوع کې وړتيا لرئ؟ د سمون وړاندیز وکړئ

In 1977 the two Voyager spacecraft left Earth on a route that uses the rare alignment of Jupiter, Saturn, Uranus and Neptune, which happens once every 175 years or so. Each planet bent their path and flung them onward faster. Without those free boosts, Voyager 2 could never have reached Neptune in twelve years.

An example flyby of Jupiter, five Jupiter radii from the centre, computed from the hyperbola's geometry. Arrows are velocities.

The planet does not give energy away. It lends you its motion.

Look

Picture a tennis ball thrown at the front of a moving train. It bounces back faster than it was thrown, because the train was moving towards it. A gravity assist is the same idea, with gravity instead of a collision:

  1. Seen from the planet, the spacecraft falls in, swings round and climbs out at exactly the same speed it came in with. Only the direction changes.
  2. Seen from the Sun, the planet itself is moving at many km/s. Add that motion to the spacecraft’s before and after the flyby: because the direction changed, the total speed can be much larger after.

Passing behind the planet, in the planet’s wake, adds speed. Passing in front takes it away; that is how Messenger slowed down to reach Mercury.

Understand

In the example, the spacecraft approaches Jupiter at v∞ = 7.5 km/s and passes 5 Jupiter radii from the centre. The hyperbola bends its direction by

δ = 2 arcsin(1/e),   e = 1 + r_p v∞² / μ

With μ_Jupiter = 1.267 × 10⁸ km³/s², e = 1.16 and the turn is about 119 degrees. Adding Jupiter’s orbital velocity (13.1 km/s):

  • Before: about 7.6 km/s relative to the Sun.
  • After: about 19.9 km/s relative to the Sun.

The spacecraft gained over 12 km/s without firing an engine. Jupiter, 10²⁴ times heavier, lost the same momentum and slowed by an amount far too small ever to measure.

Master

The largest possible change of heliocentric speed is 2 v∞ sin(δ/2), reached when the incoming and outgoing relative velocities are placed symmetrically about the planet’s velocity. The closer the pass (smaller r_p) and the more massive the planet, the larger δ can be, down to the limit set by the planet’s atmosphere or radius.

Gravity assists are a transfer of orbital energy in the three-body problem: in the planet’s frame energy is conserved; in the Sun’s frame the spacecraft’s energy changes by Δε = v_planet · Δv_rel. Mission designers chain them (Cassini: Venus, Venus, Earth, Jupiter) and add small powered flybys where a burn at closest approach profits from the Oberth effect.

هڅه کول

In the vector diagram, the outgoing arrow relative to Jupiter has the same length as the incoming one. Draw it on paper: add Jupiter's 13.1 km/s arrow to both. Which result is longer, and why does passing behind the planet (not in front of it) help?

چټکه پوښتنه

3 چټک پوښتنې. د ځواب غوره کړئ چې وګورئ که تاسو سم یاست.

  1. Relative to Jupiter, a spacecraft that flies past leaves with:

    1. A More speed than it arrived with
    2. B The same speed, in a new direction
    3. C Less speed
    4. D No speed
    ځواب ښودل

    B. The same speed, in a new direction

  2. Where does the extra speed (relative to the Sun) come from?

    1. A From the spacecraft's engines
    2. B From Jupiter's own motion around the Sun; Jupiter slows by an immeasurably tiny amount
    3. C From solar wind
    4. D It is an illusion
    ځواب ښودل

    B. From Jupiter's own motion around the Sun; Jupiter slows by an immeasurably tiny amount

  3. To gain speed, the spacecraft should pass:

    1. A In front of the planet (ahead of its motion)
    2. B Behind the planet (trailing its motion)
    3. C Straight through its centre
    4. D It makes no difference
    ځواب ښودل

    B. Behind the planet (trailing its motion)

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