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ପଥପ୍ରଦର୍ଶକ · ଏକକାଂଶ 5

Escape velocity

How fast do you need to go to leave a world for good? And why rockets do not actually need to reach it at the surface.

12 ମିନିଟ

NASA/JPL/Space Science Institute

ବିଶେଷଜ୍ଞ ସମୀକ୍ଷା ପାଇଁ ଅପେକ୍ଷା କରୁଅଛି । ଏହି ପାଠଟି AI ସହାୟତା ସହିତ ଡ୍ରାଫ୍ଟ କରାଯାଇଛି ଏବଂ ଏହାକୁ ବର୍ତ୍ତମାନ ସୁଦ୍ଧା କୌଣସି ଯୋଗ୍ୟ ସମୀକ୍ଷକ ଦ୍ୱାରା ଯାଞ୍ଚ କରାଯାଇନାହିଁ । Are you qualified in this subject? Suggest an edit

ନ୍ୟୁଟନ'ସ କ୍ୟାନନ

ସମ୍ପୂର୍ଣ୍ଣ ପୃଷ୍ଠା ଖୋଲନ୍ତୁ

ଆରମ୍ଭ ବେଗ
ଚାରିପଟେ ଘୂର୍ଣ୍ଣନ ବେଗ
ଏଠାରେ ବର୍ତ୍ତିବା ବେଗ

ପାହାଡ଼ଟି ପ୍ରକୃତରେ ଥିବାଠାରୁ ଅଧିକ ଉଚ୍ଚ ଅଟେ, ତେଣୁ ଆପଣ ଏହାକୁ ଦେଖିପାରିବେ। ବାୟୁ ପ୍ରତିରୋଧକୁ ଅବହେଳା କରାଯାଇଛି।

ତଥ୍ୟ ସାରଣୀ (ପାଠ୍ୟ ବଦଳ)

ବୃତ୍ତ ଗତିଠାରୁ ଧିରେ: ଏହା ପଛକୁ ଖସିଯାଏ। ବୃତ୍ତ ଏବଂ ପଳାୟନ ଗତି ମଧ୍ୟରେ: ଏହା କକ୍ଷପଥରେ ପରିକ୍ରମା କରିଥାଏ। ପଳାୟନ ଗତିରୁ ଅଧିକ କିମ୍ବା ସମାନ: ଏହା ସବୁଦିନ ପାଇଁ ଚାଲିଯାଏ।

ପର୍ବତର ଉପରଭାଗରେ ଆବଶ୍ୟକୀୟ ବେଗ
ଗ୍ରହଚାରିପଟେ ଘୂର୍ଣ୍ଣନ ବେଗଏଠାରେ ବର୍ତ୍ତିବା ବେଗ
ପୃଥିବୀ7.61 km/s10.8 km/s
ଚନ୍ଦ୍ର1.62 km/s2.29 km/s
ମାର୍ଚ୍ଚ3.42 km/s4.84 km/s

Throw a ball up and it comes back. Throw it hard enough and it never does. On Earth, that speed is 11.2 kilometres every second, and reaching it is why rockets are so enormous.

The Artemis I rocket lifting off at night in a blaze of light.
Artemis I lifts off from Kennedy Space Center, 16 November 2022. Credit: NASA/Bill Ingalls

Fast enough, and a thrown object never comes back.

Look

Throw a ball upwards and it comes back down. Throw it faster, it goes higher before falling back. Is there a speed so fast that it never comes back?

Yes. It is called the escape speed (or escape velocity). Go at least that fast, with nothing slowing you down, and gravity can never pull you back.

WorldEscape speed from the surface
Moon2.4 km/s
Mars5.0 km/s
Earth11.2 km/s
Jupiter59.5 km/s
Sun617.6 km/s

The Moon’s escape speed is less than a quarter of Earth’s. That is one reason why the Moon could be a useful place to launch things into space from.

In the cannon tool, the Moon is loaded. Try speeds below and above the escape speed shown in the readout.

Understand

Escape happens when the body’s kinetic energy is enough to climb out of the gravitational “well” completely. Setting kinetic energy equal to the energy needed to reach infinity:

½ v² = μ / r  ⇒  v_escape = √(2μ / r)

Compare with the circular speed √(μ/r): escape speed is always √2 ≈ 1.414 times the circular speed at the same distance.

Two important facts:

  1. It does not depend on your mass. A pebble and a spaceship need the same speed. (The spaceship needs much more energy, of course.)
  2. It depends on where you start. Farther out, r is bigger and escape is easier. From the height of geostationary orbit, Earth’s escape speed is only about 4.3 km/s.

Rockets never actually fire up to 11.2 km/s at the ground. They climb steadily while their engines keep pushing. Escape speed is the speed needed for an unpowered object, like the cannonball.

Master

In terms of specific orbital energy ε = v²/2 − μ/r, escape means ε ≥ 0. At exactly ε = 0 the path is a parabola and the speed tends to zero at infinity. Faster than that, the path is a hyperbola and the object keeps a leftover speed far away, the hyperbolic excess speed v∞:

v² = v∞² + v_escape²,   C₃ = v∞²

Mission planners quote launch energy as C₃ (km²/s²). For a Mars transfer, v∞ at departure is about 2.9 km/s, so C₃ ≈ 8.7 km²/s².

This relation hides one of the most useful effects in spaceflight, the Oberth effect: a burn made deep in a gravity well, where you are already moving fast, buys more v∞ than the same burn made far away. From a 200 km parking orbit around Earth (circular speed 7.78 km/s, escape speed 11.0 km/s), reaching v∞ = 2.9 km/s needs only about 3.6 km/s of engine burn, not 3.2 + 2.9 = 6.1 km/s. The Delta-v Map uses this for every departure from low Earth orbit.

ଏହାକୁ ଚେଷ୍ଟାକରନ୍ତୁ

On the Moon, fire at a speed just below the escape speed shown in the readout, then just above. Compare the two paths. Then try the same on Earth and Mars.

ଦ୍ରୁତ ପ୍ରଶ୍ନName

3 quick questions. Pick an answer to see if you are right.

  1. Earth's escape speed from the surface is about:

    1. A 7.9 km/s
    2. B 11.2 km/s
    3. C 29.8 km/s
    4. D 617 km/s
    Show the answer

    B. 11.2 km/s

  2. Escape speed is how many times the circular orbit speed at the same distance?

    1. A 2
    2. B √2 (about 1.41)
    3. C 1/2
    4. D π
    Show the answer

    B. √2 (about 1.41)

  3. Does escape speed depend on the mass of the object being launched?

    1. A Yes, heavier objects need more
    2. B Yes, lighter objects need more
    3. C No, only on the planet's mass and the starting distance
    4. D Only in an atmosphere
    Show the answer

    C. No, only on the planet's mass and the starting distance

Finish line

  • Played with the interactive
  • Read the lesson
  • Did the challenge
  • Took the quiz

Mark the lesson complete to save it to your progress on this device.

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